-y^2+y-12=0

Solution for -y^2+y-12=0 equation:

Simplifying
-1y2 + y + -12 = 0

Reorder the terms:
-12 + y + -1y2 = 0

Solving
-12 + y + -1y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
12 + -1y + y2 = 0

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + -1y + -12 + y2 = 0 + -12

Reorder the terms:
12 + -12 + -1y + y2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1y + y2 = 0 + -12
-1y + y2 = 0 + -12

Combine like terms: 0 + -12 = -12
-1y + y2 = -12

The y term is y.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1y + 0.25 + y2 = -12 + 0.25

Reorder the terms:
0.25 + -1y + y2 = -12 + 0.25

Combine like terms: -12 + 0.25 = -11.75
0.25 + -1y + y2 = -11.75

Factor a perfect square on the left side:
(y + 0.5)(y + 0.5) = -11.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.